Procedure: In addition to the symbols of the elements of the given type in the number of protons and electrons. Then do the electronic configuration in order to know how many valence electrons an element, or to know how much will - should be released (if metal) or as e - should receive (if nonmetal) r134a in order to achieve a stable r134a electron configuration. In addition r134a to the written symbols with the number of protons and electrons on the arrow to write the number of electrons that the element is released, or the number of electrons that element receives and then re-write the symbol of the element and the number of protons and electrons, which are the others when he was fired or receive electrons. Based on the number of laid off or received electrons to conclude that the atom become a positive or negative ion and commemorate the top right corner next to the symbol. Take into account that each element can receive or released only as electrons as there are in the valence level or how much he misses it completely filled valence level. r134a At the end of it all introduce electronic formulas and write the formula of the resulting r134a ion pair.
In this task, you will receive two elements with their Valence on the basis of which need to write a formula that they build compounds, r134a ie to specify the indexes that are the symbols of each element in the molecular formula. The procedure r134a is to first write the symbols of the given elements, unknown to record the indices x and y, then find NZS to date Velence elements and eventually sharing the DCP with the valence of the first element, specify the index x, and dividing NZS with valence other element, specify the index y. Replace the values obtained for xiyi will get the required formula.
III issue: In this issue you will be delegated to the formulas of compounds composed of two elements, one of which has a fixed valence (eg H or O), and the second variable. Your mission is based on the formula and the one known valence valence specify an unknown r134a element with variable valence. Use the rule that the product valence and the number of atoms of one element, must be equal to the valence of the product and the number of atoms of other elements.
x = 4, which means that the of compound of the formula CH 4, the valence of carbon (IV)
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