[H +] [OH -] = 10 -14 pH + pOH = 14 Example 1 Calculate the pH of a solution of hydrochloric acid

This site is dedicated to ... chemistry. What I think is well visible. For now, it is rather empty, but I try all successively completed. What can you find here? I hope to establish here a comprehensive compendium of chemical amsoil knowledge, both to help the school at the middle school and high school, as well as preparation for the exam. In the background I also have to create a bookmark with interesting experiences that can be safely performed amsoil on the circle amsoil chemical or within shows, to even a handful of biographies of famous chemists, stories to discover ... and do not know what else. Or maybe it is you who inspire me to do something?
pH and ionic product of water pH scale - a quantitative scale of acidity or alkalinity of aqueous solutions of chemicals. This scale is based on the activity of hydrogen ions [H +] in aqueous solutions.
The concept of pH introduced a Danish biochemist Søren Sørensen in 1909, pH was originally defined as the negative logarithm of the concentration of hydrogen ions (H +). Modern research has shown, however, that free hydrogen ions (free protons) never occur in aqueous solutions, as are immediately solwatowaniu according amsoil to the equation:
[H +] [OH -] = 10 -14 pH + pOH = 14 Example 1 Calculate the pH of a solution of hydrochloric acid if you know that the concentration of hydrogen ions in the solution is 0.0034 M. All necessary data we have not really given in task. The pH is calculated amsoil from the hydrogen ion concentration and it is given to us.
HCl H + + Cl - [H +] = 0.0034 M pH =-log (0.0034) = 2.47 It remains to formulate the answer: the pH of this acid is 2.47. Example 2 Calculate the concentration of NaOH solution if you know that the pOH is 6 First, we start by calculating the concentration of OH -.
pOH = 6 [OH -] = 10 -6 M Then we take for the concentration of sodium hydroxide. We know that it is a strong base and completely dissociated in aqueous solution, because it is known that the concentration of hydroxide ions is the same as the concentration of the principle.
NaOH Na + + OH - Serve answer: The concentration of this solution is 10 -6 M. Example 3 A solution of potassium hydroxide with a concentration of 0.025 M. Calculate the pH of the solution. We write equation and calculate the concentration of hydroxide ions. Because a strong base is KOH, it undergoes dissociation, and its total concentration is equal to the concentration of OH -.
ph = 14 - 1.6 = 12.4 A: The pH of this solution is 12.4. Solubility Solubility product concentrations determined threshold, which must exceed the weakly soluble amsoil salt that it has precipitated. Dissolution of the salt is equivalent to its dissociation, and therefore if we simple amsoil salt AB, then it dissociates according to the equation:
K SO = [A n +] m [B m-] n general, - when the product of the concentrations of ions in solution exceeds the solubility of the product, amsoil it will be precipitated precipitate. If it is not - not precipitate sludge. amsoil Strontium Carbonate Example 4 was dissolved amsoil in water to give a saturated solution. Calculate what is the concentration of carbonate ions and Sr 2 +, knowing that SrCO 3 solubility product is 6.3 10 -10. As with most tasks in chemistry, we start from the equation under consideration dissociation of salt and expressions to the solubility product.
SrCO 3 Sr 2 + + CO 3 2 - K SO = [Sr 2 +] [CO 3 2 -] We determine the relationship between the concentrations of the two ions. Because the salt solute ratio of the two components amsoil is 1:1 and the concentration of ions that are equal.
[Sr 2 +] = [CO 3 2 -] = x calculate the concentration of the ion. Answer: The concentration of carbonate ions and Sr 2 + is 2.51 10 -5 M each. Example 5 In a large beaker were mixed with 1 dm 3 of a 0.1 molar solution of Pb (NO 3) 2 with an equal volume of 0.1 molar solution of KBr. Knowing that the solubility product is PbBr 2 2 10 -5 calculate whether the salt precipitate is formed. We begin by calculating the concentration amsoil of the interesting ions in solution. We must remember that after mixing the solutions they undergo dilution. Save the equation and the formula for the solubility product. amsoil
Oo .. in the end is where we will make sure in your knowledge. I wanted to open a similar blog with math, so now I feel it more. One thing I know, if I had problems with chemistry, this I turn to you. Be prepared for it: D day-good-renesmee.blogspot.com Reply Delete
Very simply blended :) Since 1 dm3 each of the solutions, the final solution volume is doubled, and therefore amsoil twice the concentration decreased. [Pb 2 +] = (0.1 mol) / (2 dm3) = 0.05 mol/dm3 analogy to Remove Br-
My professor of chemistry amsoil is a wonderful man, but a teacher rather average, so thank you for your blog. He did not explain everything, but he gave the basics and helped. He can somehow help it with the more difficult issues so ago. Once again - big thank you Reply Delete
Ag Au Br interesting experience Cl Cr Cu F Fe high school experience